2019 Neco Mathematics essay and objectives verified answers expo; free 2019 Neco Mathematics runz - Teelink.Com.Ng

Teelink.Com.Ng

Best Online Websites For All Examination(WAEC,NECO,JAMB)EXPO

A serious Student would go vividly
extreme miles to see his or her success
because no one would be happy to say am
going to re- write EXAM next year! that we rejectin jesus name!!

NOTE:-TEXT OR CALL US BEFORE SUBSCRIBING. IF WE DON?T PICK YOUR CALL, JUST TEXT, ?I WANT TO SUBSCRIBE FOR WAEC (OR ANY KIND OF EXAMINATION YOU WANT TO WRITE)? TO OUR NUMBER(08059947056)

CLICK HERE TO CHAT WITH US DIRECTLY ON WHATSAPP


Hot: Click Here For Latest School News, University, College, Scholarships And ...Education Updates!


JAMB 2019
WAEC 2019
How to Score 250 ? 270+ Flat In Your 2019/2020 Jamb CBT Exam (EXPO/RUNZ/RUNS)
2019 WAEC WASSCE EXPO: CONFIRM YOUR WAEC 2019 DETAILS IN OUR DATABASE EXPO
Click Here

Monday, 24 June 2019

2019 Neco Mathematics essay and objectives verified answers expo; free 2019 Neco Mathematics runz

Continue reading after the advertisement... [CLICK HERE=> Facebook Leaked s3x Video: The Guy Who Rushed Giving His Girl Many S3x Styles But Lasted 1 Min]
2019-NECO-MATHEMATICS-ANSWERS

================================


MATHS-OBJ
1-10: DBBCBDEDAC
11-20: DCDAECDEDC
21-30: CBAAECDCAD
31-40: CCACCBDDCC
41-50: CDDDCABDBA
51-60: BCBDBCAADD
============THEORY===============

1.

I=PxRxT/100

interest for the 1st year
I =110,000 x 5 x 1 / 100
=#5,500
Amount=#110,000 + #5,500 + #50,000

Amount=#165,500.00
INTEREST FOR 2ND YEAR
I = 165,500 * 5 * 1 /100
=#8,275.00
AMOUNT= #165,500 + #8,275 + #50,000
AMOUNT= #223,775.00

INTEREST FOR 3RD YEAR
I = 223,775 x 5 x 1 / 100
= #11,118.75
AMOUNT= #223,775+#11,118.75+#50,000
=#284,963.75

a). Her total savings after 3 years=#284,963.75

b). Her savings is less than #300,000.00 by #(300,000-284,963.75)
#15,036.25
*===============================================================*

(2a)
3^2x-y=1
3^2x-y=3^0
2x-y=0-------------(1)
16^x/4 = 8^3x-y
2^4x/2^2 = 2^3(3x-y)
2^4x-2 = 2^9x-3y
:. 4x-2 = 9x-3y
4x-9x+3y= 2
-5x+3y=2------------(2)
From equation (1):
2x-y=0
y=2x--------(3)
Substitute for y in equation (2)
-5x+3y=2
-5x+3(2x)=2
-5x+6x=2
x=2
Substitute for x in equation (3)
y=2x
y=2(2)=4
:.x=2, y=4

(2b)
x² - 4/3 + x+3/2
2(x² - 4) + 3(x +3)/ 6
2x² - 8 + 3x + 9/6
2x²+3x+1/6
(2x² + 2x)+(x+1)/6
2x(x+1) +1 (x+1)/6.
*===============================================================* 
(3)
Using SOHCAHTOA
|TM| / |MD| = Tan28°

298.5+1.5/|MD| = 0.5317
|MD| = 300/0.5317 = 564.2m

Similarly,
|TM| / |MC| = Tan34°
300/ |MC| = 0.6745
|MC| = 300/0.6745 = 444.8m

Distance between both , ΔCD
= 564.2 - 444.8
= 119.4m
SEE THE IMAGE(3)
*=========================
======================================* 
 
(4)
Mark: 1-5, 6-10, 11-15, 16-20, 21-25, 26-30
F: 6,4,5,5,6,4
x: 3,8,13,18,23,28
Fx: 18,32,65,90,138,112
x-x: -12.167, -7.167, -2.167, 2.833, 7.833, 12.833
(x-x)^2: 148.0359, 51.3659, 4.6959, 8.0259, 61.3559, 164.6859
f(x-x)^2: 888.2154, 205.4636, 23.4795, 40.1295, 368.1354, 658.7436

Mean(x) = Σfx/Σf = 455/30 =15.167
Variance = Σf(x-x)^2/Σf = 2184.167/30 = 72.8056
= 72.81(approximation.)

Standard deviation = √Variance
= √72.84
= 8.533
= 8.53 (approximation.)
SEE IMAGE(4)
*=====================
==========================================* 
5a
X²-5x-24=0
X²-5x=24
Add to both sides the square of half the coefficient of x
X²-5x+(-5/2)²=24+(-5/2)²
(X-5/2)²=121/4
X-5/2=±11/2
X=5/2±11/2
X=8 or -3
*===============================================================* 
(6a)
For X = a=4a , T6=256
ar^5=256
4ar^5/4=256/4
ar^5=64............(1)

For Y = a=3a, T5=48
ar^4=48
3ar^4/3=48/3
ar^4=16...............(2)

Divide equ (2) by (1):
ar^5/ar^4=64/16
r=4

Substitute for r in equ (2)
ar^4=16
a × 4^4=16
256a/256=16/256
a=1/16

(6ai)
First term of x : a=4a
a=4×1/16=1/4

(6aii)
Sn = a(r^n-1)/r-1
S4 = 1/4(4^4 -1)/4-1
=1/4(256-1)/3
=1/4 × 255/3
=85/4
S4=21.25

(6b)
y(4x+2)^-3
Let u =4x+2, y=u^-3
du/dx=4, dy/du= -3u^-4
dy/dx=dy/du * du/dx

= -3u^-4 × 4
= -12u^-4
dy/dx= -12(4x+2)^-4

When x =1,
dy/dx= -12(4*1+2)^-4
= -12(4+2)
= -12 * 6^-4
= -12/6^4
= -12/1296
= -1/108
*===================
============================================* 
(7a)
4x^2 - 9y^2 = 19
2x^2 x^2 - 3^2 y^2=19
(2x-3y)(2x+3y)=19

Substitute for 2x+3y=1
2x-3y=19............(1)
2x+3y=1..............(2)

Subtract equ (2) from (1)
2x-3y-(2x+3y)=19-1
3x-3y-2x-3y=18
-6y/-6=18/-6
y = -3

Substitute for y in equ (1)
2x-3(-3)=19
2x+9=19
2x/2=10/2
x=5

(7b)
Typing
SEE IMAGE(7)
*===============================================================* 
(8ai)
Total surface area
= Total surface of cylinder + Curve surface of hemisphere
= (πr^2+2πrh) + (2πr^2)
= π(r^2 + 2rh) + π(2r^2)
= π[(r^2 + 2rh) + 2r^2]
= π[(7^2 + 2(7)(10) + 2(7)^2]
= π[(49+140) + 98]
= π(287)
= 287πcm^2

Using π=22/7
Total surface area =287×22/7 = 41×22
= 902cm^2

(8aii)
Volume = Volume of cylinder + volume of hemisphere
= πr2h + 2/3πr^3
= π[r^2h + 2/3r^3]
= π[(7^2)(10) + 2/3(7)^3]
= π(490 + 656/3)
= π(2156/3)
= 22/7 × 2156/3
= 22 × 308/3 = 6776/3
= 2258.67cm^3

(8b)
Perimeter of Arc = Φ/360 × 2πr
= 120/360 × 2 × 22/7 × 7
= 1/3 × 44 = 44/3
= 14.67cm
SEE IMAGE(8)
*===============================================================*
(10ai)
S=t^3 -3t -9t + 1
ds/dt=v
:. 3t^2 - 6t^2 -9
When v=0
3t^2 -6t^2 -9=0
(3t^2 -9t)+(3t-9)
3t(t-3)+3(t-3)=0
(3t+3)(t-3)=0
3t + 3=0
3t= -3
t= -3/3= -1 or t -3=0
t=3seconds

(10aii)
a=dv/dt = 3t^2 -6t -9= 6t -6
a=6t -6
When a=0
6t -6=0
6t=0+6
6t=6
t=6/6
t=1

(10b)
v=3t^2 -6t -9
When t=2seconds
v=3(2)^2 -6(2) -9
= 3*4-9-12-9= -9m/s
v= -9m/s
acceleration, a when t=2seconds
a=6t -6= 6(2) -6= 12-6
a=6m/s^2

(10c)
a=6t -6 = 36-6=30
a=30m/s^2
SEE IMAGE(10)
*=====================
==========================================*

No comments:

Post a Comment


offeroffer
Do You Love The Current Design Of This Blog? We Can Set Up Same Design For You At An Affordable Price.

Click Here Now To Get Started!


HOME | DISCLAIMER | CONTACT US | ABOUT | PRIVACY POLICY
SITEMAP

Copyright © 2019. Powered by TeeLink.